If the sensor has a resoultion of 14-Bit linear, then it can#t be saved in 8-Bit without compression or loss of data.
No it can't indeed. But neither can it in 16bit linear space, can it?
If you use the data and just give it more space (16-Bit).
The data can be saved without loss, if the 14-Bit data is linear.
If it is not, then 16-Bit might be even to small...
...we then go into sensor details.
We would have to look into the characteristic curve of the sensor,
to look at what the sensor provides.
If the sensors are already provide 14-Bit through a logartithmic curve
(what is new to me, that they do), then there should also be much more
resolution possible...
And when we say, 14-Bit are from a logarithmic curve, we have to distinguish
where the 14-Bits are.
Is the input range aequivlanet to 14-bits, but the output range is just 10 bits or less?
Or is the OUTPUT aequivalent to range 14-bit linear?
If the later, it firs nicely into the 16-bit
And if the former, then it fits into it even better.
I meant: if there are 14-Bit linear output data... then it fits.
If there aree 14-Bit log. output, the sensor resoultiion would be much higher.
I doubt that, because if so, the marketing would have used the aequivalent
linear number and would have called it maybe 18-bit sensor.
So maybe it's 14-bit input range, logarithmic curve creating 10-bit output data, and after raw-conversion is again 14-bits wide, linear, and can be stored in 16-bit format better than in 8-Bit.
EDIT: some clarifications on the used words added.